Question 1.
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6, 9.
The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
Answer
target = 1000
mult3or5 = []
for i in range(target):
while i*3 < target and i*3 not in mult3or5:
mult3or5.append(i*3)
while i*5 < target and i*5 not in mult3or5:
mult3or5.append(i*5)
print(sum(mult3or5))
Returns
233168
